A car travelling with 5/7 of its actual speed covers 42 km in 1 hr 40 min 48 sec. Find the actual speed of the car.
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Answered by
0
Let actual speed of car be x
Car is travelling 5 /7 of x
Distance travelled =42 km
Time taken = 1 hr 40 min 48 sec =100 .80 min
speed =distance /time
5/7 x =42 /100. 80
504 x =294
504/ 294 =x
1.71428...
1.7143 km /hr =x ...
Sorry for any mistake
Car is travelling 5 /7 of x
Distance travelled =42 km
Time taken = 1 hr 40 min 48 sec =100 .80 min
speed =distance /time
5/7 x =42 /100. 80
504 x =294
504/ 294 =x
1.71428...
1.7143 km /hr =x ...
Sorry for any mistake
Answered by
3
A car travelling with 5/7 of its actual speed covers 42 km in 1 hr 40 min 48 sec.
Time taken = 1 hr 40 min 48 sec
=1 hr 40 4/5 min
= 1 51/75 hrs
=126/75 hrs
Let the actual speed be 'x' kmph
5/7 of actual speed →5x/7
Speed×time = distance
5x/7 × 126/75 = 42 km
x = (42×75×7)/(126×5)
x = 22050/630
x = 35 km/hr
Therefore,actual speed = 35 km/hr
Time taken = 1 hr 40 min 48 sec
=1 hr 40 4/5 min
= 1 51/75 hrs
=126/75 hrs
Let the actual speed be 'x' kmph
5/7 of actual speed →5x/7
Speed×time = distance
5x/7 × 126/75 = 42 km
x = (42×75×7)/(126×5)
x = 22050/630
x = 35 km/hr
Therefore,actual speed = 35 km/hr
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