A car travelling with 5/7 of its actual speed covers 42 km in 1 hr. 40 min 48 seconds. find the actual speed of the car.
Answers
Answered by
19
first convert this time into hours
1 hr 40min 48sec= 1 + 40/60 + 48/(60 x 60) hrs
=1+ 2/3 + 4/300
=(300+200+4)/300
=504/300
=126/75 hrs
Let the actual speed be x km/hr.
then
(5x/7) x (126/75) = 42
so x = (42 x 75 x 7) / (126 x 5)
x = 35 km/hr
i hope it will help you
regards
1 hr 40min 48sec= 1 + 40/60 + 48/(60 x 60) hrs
=1+ 2/3 + 4/300
=(300+200+4)/300
=504/300
=126/75 hrs
Let the actual speed be x km/hr.
then
(5x/7) x (126/75) = 42
so x = (42 x 75 x 7) / (126 x 5)
x = 35 km/hr
i hope it will help you
regards
Answered by
3
Answer:
Step-by-step explanation:
1 hr = 60 min
1 min = 60 secs
So start with 48 secs first which is 48/60 min = 0.8 min
Now, it is 1 hr 40.8 min.
40.8/60 = 0.68 hr
So the time covered is 1.68 hrs.
speed = distance/time
(5/7)*actual speed = 42 km / 1.68 hr
(5/7)*actual speed = 25
actual speed = 25*(7/5) = 35 km/hr
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