A car travelling with a constant speed of 24 ms -
along South to North direction crosses a intersection
at time t = 0. Another car moving with speed of
30 ms-t along West to East direction crosses the
intersection at t = 5 s. The displacement between
them at t = 2 second is
Answers
A car travelling with a constant speed of 24 m/s along south to north crosses an intersection O at t = 0. another car moving with speed of 30 m/s along west to east crosses the same intersection at t = 5 s.
To find : The distance between them at t = 2s
solution : let both cars cross the intersection point is located at origin.
at t = 0,
position of 1st car = origin = (0,0)
position of 2nd car = (-v₂t, 0) = (-30 × 5, 0) = (-150, 0)
at t' = 2,
position of 1st car = (0, v₁t') = (0, 24 × 2) = (0, 48)
position of 2nd car = (-150 + v₂t', 0) = (-150 + 30 × 2, 0) = (-90, 0)
now seperation between them = distance between two points (0, 48) and (-90, 0)
= √{(-90)² + (48)²}
= √{8100 + 2304}
= √{10404}
= 102
Therefore the distance between them at t = 2s, is 102 m
