Question

a car travelling with a speed 72 km/h applies brakes if it experiences a constant retardation of 40 m/s^2. calculate the stopping distance. ​

Answer 1

Answer:

First convert the velocity to m/s from km/h. Here, you get it as 20 m/s.

Now, you have final velocity: v = 0 m/s as the body is going to come at rest.

Whole initial velocity: u = 20m/s,

The acceleration is retarding in nature

So, you have a = (-2 m/s²)

Using the Kinematic Equation : v=u+at you get t = 2s

And using v²=u²+2as

You have s=v²/2as = 400/(2)(2),

i.e. s = 100 m