Question

a car travelling with a speed of 1 metre per second applies brakes and came to rest with an acceleration of - 0.5 metre per second square what is the distance travelled by the car before coming to rest​

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Distance\:travelled=1\:m}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies Initial \: speed(u) = 1 \: m/s \\ \\ \tt: \implies Acceleration(a) = - 0.5 \: m /{s}^{2} \\ \\ \red{\underline \bold{To \: Find:}} \\ \tt: \implies Distance \: travelled \: by \: car = ?$

• According to given question :

$\tt \circ \: Final \: speed = 0 \: m/s \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies {v}^{2} = {u}^{2} + 2as \\ \\ \tt: \implies {0}^{2} = {1}^{2} + 2 \times ( - 0.5) \times s \\ \\ \tt: \implies - 1 = - 1 \times s \\ \\ \green{\tt: \implies s = 1 \: m} \\ \\ \bold{\blue{Some \: related \: formula }} \\ \orange{\tt \circ \: v = u + at} \\ \\ \orange{\tt \circ \:s = ut + \frac{1}{2} at}$

Answer 2

$\tt{\red{\huge{Hello!!! }}}$

Question :

A car travelling with a speed of 1 metre per second applies brakes and came to rest with an acceleration of - 0.5 metre per second square what is the distance travelled by the car before coming to rest.

Solution :

$\tt{\orange {Step-By-Step-Explaination \::- }}$

Formula Used :

$\tt{ \purple{ \leadsto{ {v}^{2} = {u}^{2} + 2as }}}$

Placing the values

$\tt{ \purple{ \leadsto{ {0}^{2} = { - 1}^{2} + 2( - 0.5)s }}}$

S = 1 m.

Additional Formulae :

$\tt{ \purple{ \leadsto{ {v}^{2} = {u}^{2} + 2as }}}$

$\tt{ \purple{ \leadsto{ v = u + at }}}$

$\tt{ \purple{ \leadsto{ s = ut + \dfrac{1}{2} a {t}^2}}}$