a car travelling with a speed of 20 km how was come into rest in 0.5 hours what will be a value of its relation
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Answered by
27
Hello Mate!
v = 0
u = 20 km/h
t = 0.5 h
First deriviation of motion = v = u + at
0 = 20 + a(0.5)
-20 = 0.5a
-20/0.5 = a
-20 × 10/5 = a or a = - 40 km/h^2
Value of Retardation = 40 km/h^2
Hope it helps☺!✌
v = 0
u = 20 km/h
t = 0.5 h
First deriviation of motion = v = u + at
0 = 20 + a(0.5)
-20 = 0.5a
-20/0.5 = a
-20 × 10/5 = a or a = - 40 km/h^2
Value of Retardation = 40 km/h^2
Hope it helps☺!✌
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Answered by
6
Hello Mate!
v = 0
u = 20 km/h
t = 0.5 h
First deriviation of motion = v = u + at
0 = 20 + a(0.5)
-20 = 0.5a
-20/0.5 = a
-20 × 10/5 = a or a = - 40 km/h^2
Value of Retardation = 40 km/h^2
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