Chemistry, asked by jka30583, 4 months ago

A car travelling with a velocity of 40m/s came to rest in 8s.What is its acceleration


A) -5 m/s²
B) -4 m/s²
C) 8 m/s²
D) 2 m/s²

Answers

Answered by yuvika9586
1

Answer:

u= 40 m/s , v= 0m/s ,t= 8s

v= u+at

a= v- u /t = 0- 40/ 8 m/ s2

= - 5 m/s2

Explanation:

so answer is option a

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Answered by nishantseth46
1

Answer:

Its a

Explanation:

Since we know that

a =  \frac{u - v}{t}  \\ a =  \frac{0 - 40}{8}  \\ a =  \frac{ - 40}{8}  \\ a =  - 5m \:  {s}^{ - 1}

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