A car travelling with a velocity of 80 km/h slowed down to 44 km/h in 15 s. The retardation is
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Answered by
108
Initial Velocity = 80 km/h
Final Velocity = 44 km/h
Time = 15 seconds
Acceleration/Retardation = 44-80 divided by 15 = -36/15 = -2.4
The retardation is 2.4
Final Velocity = 44 km/h
Time = 15 seconds
Acceleration/Retardation = 44-80 divided by 15 = -36/15 = -2.4
The retardation is 2.4
Paritosh30:
the retardation is 0.67m/s-2 (here -2 is power)(approx)first convert the given velocities in m/s and then find the retardation by dividing their difference by time
Answered by
360
Hello friend
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Initial velocity of the car is 80kmph
80×5/18=200/9 m/sec
It slowed down to 44kmph
44×5/18=110/9 m/sec
Time taken is 15sec
Retardation is [(200/9)-(110/9)]÷15
=(90/9)÷15
=10/15=0.666...=0.67m/s^-2
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Hope it helps!
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Initial velocity of the car is 80kmph
80×5/18=200/9 m/sec
It slowed down to 44kmph
44×5/18=110/9 m/sec
Time taken is 15sec
Retardation is [(200/9)-(110/9)]÷15
=(90/9)÷15
=10/15=0.666...=0.67m/s^-2
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Hope it helps!
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