Physics, asked by jadhavcsdad, 9 months ago

A CAR TRAVELLING WITH VELOCITY OF 80 KM/HRSLOWED DOWN TO 44 KM/HR IN 15S THE RETARDATION IS

Answers

Answered by dharmendrasinghasr01
0

Answer:

V-u=at

u=80 km/h=22.22m/s

v=44km/h=12.22m/s

t=15s

v-u=at

12.2-22.22=a*15

-10/15=a

a=-2/3m/ s^{2}

Explanation:

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Answered by Rupkathadas
2

Answer:

The initial velocity is u=80 km/hr. The final velocity is v=44 km/hr. The time taken is t=15 s. Therefore, The retardation is -0.66 m/s².

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