A car travells along a straight line for the first half time with speed 50km/h and the second half time with the speed of 60km/h.Find the average speed of the car.
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4
Suppose the car takes time t to complete the journey.
It travels for time t/2 at speed 40 km/h. So, the distance travelled in this t/2 is = 40t/2 = 20t
It travels the next time t/2 at speed 60 km/h. So, the distance travelled in this t/2 is = 60t/2 = 30t
Now,
Average speed is = total distance/total time = (20 t + 30t)/t = 50 km/h
It travels for time t/2 at speed 40 km/h. So, the distance travelled in this t/2 is = 40t/2 = 20t
It travels the next time t/2 at speed 60 km/h. So, the distance travelled in this t/2 is = 60t/2 = 30t
Now,
Average speed is = total distance/total time = (20 t + 30t)/t = 50 km/h
Joshuawoskk:
Pls mark as brainliest and follow if your intersted
answer is 55
You mistakenly took 40kmph instead of 50kmph
No answer will be 55
Sorry about that
its ok cause the formula is right
Answered by
1
Distance travelled in
1st half time = 50kmph × T/2
2nd half time = 60kmph × T/2
Average speed = Total Distance / Total time
= [(50 + 60)T/2] / T
= (50 + 60) / 2
= 55 kmph
Average speed of car = 55 kmph
1st half time = 50kmph × T/2
2nd half time = 60kmph × T/2
Average speed = Total Distance / Total time
= [(50 + 60)T/2] / T
= (50 + 60) / 2
= 55 kmph
Average speed of car = 55 kmph
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