A car travells with a velocity of 72 km/h in 10s , starting from rest .
(a) Find acceleration
(b) average velocity.
(c) distance travelled .
Please solve it.
Most satisfying answer will mark as brainliest.
Answers
Answer:
(a) Acceleration ( a ) = 2 m / sec²
(b). Average velocity = 10 m / sec
(c) Distance travelled = 100 m
Explanation:
Given :
Initial velocity ( u ) = 0 m / sec
Final velocity ( v ) = 72 km / hr
To convert km / hr into m / sec multiply it by 5 / 18 we get
v = 4 × 5 = 20 m / sec
Time ( t ) = 10 sec
a .
From first equation of motion we have
v = u + a t
put the value here
20 = 0 + a × 10
10 a = 20
a = 2 m / sec² .
b.
Average velocity = u + v / 2
Average velocity = 0 + 20 / 2
Average velocity = 20 / 2 = 10 m / sec
c.
We have second equation of motion
s = u t + 1 / 2 a t²
put the value here
s = 0 + 1 / 2 × 2 × 10 × 10
s = 10 × 10
s = 100 m
Thus we get all answer.
» A car travells with a velocity of 72 km/h in 10s.
Here ..
• Final velocity (v) = 72 km/hr
=> 72 ×
=>
=> 20 m/s
• Time (t) = 10 sec
• Initial velocity (u) = 0 m/s (as said in question car travells with a velocity of 72 km/h in 10s, starting from rest. Means it's initial velocity (from starting) is zero)
______________ [ GIVEN ]
• We have to find : a) Acceleration (a)
b) Average velocity
c) Distance travelled (s)
______________________________
a) v = u + at
(From First Law Of Motion)
Put the known values in above formula
=> 20 = 0 + a(10)
=> 20 = 10a
=> 10a = 20
=> a = 2 m/s²
_________ [ ANSWER ]
______________________________
b) Average velocity =
=>
=>
=> 10 m/s
__________ [ ANSWER ]
_____________________________
c) s = ut + at²
Put the known values in above formula
=> s = 0(10) + (2)(10)²
=> s = + 200
=>s =
=> s = 100 m
____________ [ ANSWER ]
______________________________