A car travels 1/3 of the distance on a straight road with a velocity of 10 km/h, the next 1/3 with a velocity of 20 km/h and the last 1/3 with a velocity of 60 km/h. What is the average velocity of the car for the whole journey?
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Let x=total time
y = total distance
Then: (use T=D/R)
Time for first 1/3 of distance = ( (y/3)/ 10 )
Time for second 1/3 of distance = ( (y/3)/20 )
Time for third 1/3 of distance = ( (y/3)/60 )
Time for entire trip = x = ( (y/3)/10 ) + ( (y/3)/20 ) + ( (y/3)/60 )
180x = 6y +3y + y
180x = 10y
x = y/18
Rate for entire trip = D/T = y/x
= y / (y/18)
= y * (18/y)
= 18 km/hr
hope it helps !! ☺☺
y = total distance
Then: (use T=D/R)
Time for first 1/3 of distance = ( (y/3)/ 10 )
Time for second 1/3 of distance = ( (y/3)/20 )
Time for third 1/3 of distance = ( (y/3)/60 )
Time for entire trip = x = ( (y/3)/10 ) + ( (y/3)/20 ) + ( (y/3)/60 )
180x = 6y +3y + y
180x = 10y
x = y/18
Rate for entire trip = D/T = y/x
= y / (y/18)
= y * (18/y)
= 18 km/hr
hope it helps !! ☺☺
Harry098:
Hi
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