A car travels 1/4th of a circle with radius r. Find the ratio of the distance to its displacement
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Hey.
Here is the answer.
As car travels 1/4 the of a circle
so, distance covered , d = 1/4 of circumference
or, d = 1/4 × 2πr
or, d = 1/2 πr
Displacement :
As the displacement is shortest path between initial and final position
So , it will be the hypotenuse of the right angle triangle of both sides r.
So, D = √(r^2 + r^2) = √2r^2 = r√2
Hence ratio of d/D = 1/2 πr / r√2
= π / 2√2
or, d : D = π : 2√2
Thanks .
Here is the answer.
As car travels 1/4 the of a circle
so, distance covered , d = 1/4 of circumference
or, d = 1/4 × 2πr
or, d = 1/2 πr
Displacement :
As the displacement is shortest path between initial and final position
So , it will be the hypotenuse of the right angle triangle of both sides r.
So, D = √(r^2 + r^2) = √2r^2 = r√2
Hence ratio of d/D = 1/2 πr / r√2
= π / 2√2
or, d : D = π : 2√2
Thanks .
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