a car travels 10 km distance at a speed of 60 km/h and returns with a speed of 40 km/h. calculate its average speed for the whole journey.
please answer fast...
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2
case 1
speed of car - 60km/h
distance- 10km
speed=distance/time
60=10/time
time=10/60
time=1/6hr
case 2
speed =40km/hr
distance=10
speed=dis/time
40=10/time
time=10/40=1/4hr
average speed=total distance/total time
a.v=10+10
--------------
1/6+1/4
a.v=20
------------
10/24
a.v=20×24/10
a.v=48km/hr
speed of car - 60km/h
distance- 10km
speed=distance/time
60=10/time
time=10/60
time=1/6hr
case 2
speed =40km/hr
distance=10
speed=dis/time
40=10/time
time=10/40=1/4hr
average speed=total distance/total time
a.v=10+10
--------------
1/6+1/4
a.v=20
------------
10/24
a.v=20×24/10
a.v=48km/hr
prajjwalrai:
for distance1 time = put 40km/h = 10 / t.. so t = 10 /40
and for distance 2 put time = distance / speed... 10 / 60
a.v = total distance / total time
now i understnd
thanks
10 + 10 ÷ 10 / 40 +10 /60
and u will get ur ans
i understood
which is 48 km / hour
20 km / h is wrong
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