A car travels 100 km distance such that 50 km distance with the speed of 80 km/hour, find the speed of the car for the remaining 50 km if average speed of car is 50 km/hour.
B) A body covers total distance z such that first one fourth of distance of z with the speed of 10 km/h, second one fourth of distance z with the speed 20 km/h, third one fourth of distance z with the speed of 30km/h and last one fourth of distance z with the speed 40 km/h. find the average speed of body.
Answers
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Answer:
Answer:
90 km/hr fast must the car travel for the next 50 km
Explanation:
Given that,
Total distance = 100 km
First distanced_{1} = 50\ kmd
1
=50 km
Speedv_{1} = 30\ km/h^{-1}v
1
=30 km/h
−1
The car travels 50 km with speed 30 km/hr.
The time taken is
t=\dfrac{d}{v}t=
v
d
t_{1}=\dfrac{50}{30}t
1
=
30
50
t_{1}= 1.67\ hrt
1
=1.67 hr
Let us consider, the car travels next 50 km with speed v₂ km/hr.
The time taken is
t_{2}= \dfrac{50}{v_{2}}t
2
=
v
2
50
The average speed v_{avg}=\dfrac{D}{T}v
avg
=
T
D
Here, D = total distance
T= total time
The average speed is
45=\dfrac{100}{\dfrac{5}{3}+\dfrac{50}{v_{2}}}45=
3
5
+
v
2
50
100
v_{2}=90\ km/hrv
2
=90 km/hr
Hence, 90 km/hr fast must the car travel for the next 50 km.
Explanation:
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