Question

A car travels 10km at highway speed (100km/h) against a frictional force of F=0.42v². If the engine is 20% efficient how much gasoline was used when Shc=34MJ/litre

Answer 1

Step-by-step explanation:

Energy consumed by car

= 0.42 (100)^2 × 10 × 100/20 = 0.21 × ( 100)^ 3

= 21 MJ

Gasoline used = 21/34 = 0. 617 litre.