a car travels 20 km at a uniform speed of 40 km / hr and the next 20 km at a speed of 60 km / hr .find its average speed.
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Answered by
1
v = d/t
t = d/v
t1 = d1/v1
t2 = d1 /v2 (because d1 = d2 = 20km)
Vav = total distance/time
Vav = d1+d1/(d1/v1 + d1/v2)
Vav = 2d1/(d1V1+d1V2/V1V2)
Vav = 2V1V2/V1+V2
use this formula
Vav = 2V1V2/V1+V2
Vav = 2(40)(60)/40+60
Vav = 4800/100
Vav = 48km/h
t = d/v
t1 = d1/v1
t2 = d1 /v2 (because d1 = d2 = 20km)
Vav = total distance/time
Vav = d1+d1/(d1/v1 + d1/v2)
Vav = 2d1/(d1V1+d1V2/V1V2)
Vav = 2V1V2/V1+V2
use this formula
Vav = 2V1V2/V1+V2
Vav = 2(40)(60)/40+60
Vav = 4800/100
Vav = 48km/h
Answered by
0
Given Initial speed=40km /hr Final speed =60km/hr First he cOvers 20 km So Av speed= initial speed + final speed ÷2 40+60÷ 2=100÷2=50km/hr
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