A car travels 200kms at a speed of 60km/hr and returns at speed of 40km/hr. What must be it's average speed
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S1 = 40 km/hr
S2 = 60 km/hr
So now let us assume that the distance between a and b will be 120 km ( LCM of 40 and 60 )
D1 = 120 km
D2 = 120 km
Total Distance = D1 + D2 = 120 + 120 = 240 km
Now
T1 = D1/S1
T1 = 120/40 = 3 hr
T2 = D2/S2
T2 = 120/60 = 2 hr
Total Time = T1 + T2 = 3 + 2 = 5 hr
Now
Average Speed = Total Distance / Total Time = 240 / 5
Average Speed = 48 km/hr
Edit: 28 July 2017
You can also solve this que using a simple formula
Avg Speed = 2xy/x+y
x = 40 and y = 60
Avg Speed = 2 x 40 x 60/100
Avg Speed = 48 km/h
S2 = 60 km/hr
So now let us assume that the distance between a and b will be 120 km ( LCM of 40 and 60 )
D1 = 120 km
D2 = 120 km
Total Distance = D1 + D2 = 120 + 120 = 240 km
Now
T1 = D1/S1
T1 = 120/40 = 3 hr
T2 = D2/S2
T2 = 120/60 = 2 hr
Total Time = T1 + T2 = 3 + 2 = 5 hr
Now
Average Speed = Total Distance / Total Time = 240 / 5
Average Speed = 48 km/hr
Edit: 28 July 2017
You can also solve this que using a simple formula
Avg Speed = 2xy/x+y
x = 40 and y = 60
Avg Speed = 2 x 40 x 60/100
Avg Speed = 48 km/h
Ronaksinh999:
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