Question

A car travels 22 km south, 12 km west, and 14 km north in half an hour.
a) What is the average speed of the car?
b) What is the final displacement of the car?
c) What is the average velocity of the car?

Answer 1

Answer:

a) averaged speed is 16km/h

b) 8km

c) 16km/h

Explanation:

average speed: total distance/total time

22+12+14/0.5

96km/h

average velocity= displacement/total time

8/0.5= 16km/h

**

Answer 2

Answer:

The correct answer are 21.11m/s, 14420m and 8.01m/s.

Explanation:

Given:

S = 22+12+14

  = 38Km

  = 38000m

T = 1800s

Here,

The total distance is denoted by X.

The time is denoted by T.

The displacement is denoted by D.

The average velocity is denoted by V.

The average speed is denoted by S.

Now,

For part A,

By the equation,

$S=\frac{X}{T} \\S=\frac{38000}{1800}\\S= 21.11m/s$

So, the average speed is 21.11m/s.

Then,

For part B,

D = $\sqrt{(22-14)^{2}+ 12^{2} }$

   = 14.42Km

   = 14420m

So, the sisplacement is 14420m.

Then,

For part C,

By the equation,

$V=\frac{D}{T} \\V=\frac{14420}{1800}\\V= 8.01m/s$

So, the average velocity is 8.01m/s.