A car travels 3 cm east then 4 cm north . How far would it travel if it drive directly back to its starting point?
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A car travels 6 km towards north at an angle of 45^o to the east and then travels distance of 4 km towards north at an angle 135^o to east. How far is the ...
Net distance traveled along x - direction, SX = 6cos45^oî - 4cos45^oî = 2 × 1/√(2) = √(2) km Net distance traveled along y - direction Sy = 6sin45^oĵ ..
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