Question

A car travels 6km towards north at angle of 45 degree to east then travels distance of 4km towards north at an angle of 135 to the east how far is the point from the starting point . What angle does the straight line joining its initial and final position makes with east ////////////////\\

Answer 1

HELLO DEAR,

now, net distance along x-direction.

Sx= 6cos45°-4cos45°

Sx= 2cos45°

Sx = 2*1/root2= root2km

net distance along y-direction

Sy= 6cos45°+4cos45°

Sy= 10cos45°

Sy= 10*1/root2= 5root2 km

net distance travelled from the starting point ,

Root(Sx)^2+(Sy)^2

Root(root2) ^2 +(5root2) ^2

Root(2+50)

Root(52)

now,the angle which resultant make with east direction

Tan(theta) = y-componenet/x-component

Tan(theta) = 5root2/ root2 = 5

Theta= tan^1(5)

I HOPE ITS HELP YOU DEAR,

THANKS

Answer 2

Answer is root 52 and tan ^-1(5)

See the diagram

Hope it will help you

Thanks