Question

a car travels 900m in which each wheel makes 450 complete revolution. Find the radius of the wheel​

Answer 1

Answer :-

➝ The radius of the wheel is 0.32m .

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Explanation :-

$\sf{\huge{\underline{\red{Given :-}}}}$

• A car travels 900m.

• Each wheel makes 450 complete revolution.

$\sf{\huge{\underline{\green{To\:Find :-}}}}$

• The radius of the wheel.

$\sf{\huge{\underline{\purple{Solution :-}}}}$

Let the radius of wheel be r cm.

The perimeter of wheel = Circumferance of wheel = 2 π r

• The wheels makes 450 revolution.

Total distance covered by the wheel = No.of revolution × Circumferance of wheel

➝ Total distance covered by the wheel = 450 × 2πr

➝ Total distance covered by the wheel = 900πr

• Total distance covered by the wheel is 900m.

➝ 900 = 900πr

➝ πr = $\cancel{\dfrac{900}{900}}$

➝ πr = 1

➝ r = $\dfrac{1}{\pi}$

➝r = $\dfrac{1}{22/7}$

➝ r = $\dfrac{7}{22}$

➝ r = 0.32m

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Answer 2

☆Given Question :-

• A car travels 900m in which each wheel makes 450 complete revolution. Find the radius of the wheel.

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$\bf \:\large \purple{AηsωeR : 1.} ✍$

$\large \red{\sf \: Given :- }$

• A car travels 900m in which each wheel makes 450 complete revolution.

$\large \green{\sf \:  To  \: Find :- }$

• The radius of the wheel.

$\begin{gathered}\Large{\bold{\pink{\underline{Formula \: Used \::}}}}\end{gathered}$

${{ \boxed{\large{\bold\purple{Perimeter_{(Circle)}\: = \:2\pi r }}}}}$

$\begin{gathered}\Large{\bold{\orange{\underline{CaLcUlAtIoN\::}}}} \\ \end{gathered}$

$\begin{gathered}\longmapsto\:\:\bf{Let \: Radius \: of \: wheel \: \:is \:r\:m}. \\ \end{gathered}$

$\begin{gathered}\begin{gathered}\bf Car = \begin{cases} &\sf{wheel \: make \: 450 \: revolutions} \\ &\sf{travelled \: a \: distance \: of \: 900 \: m} \end{cases}\end{gathered}\end{gathered}$

□ We know,

☆ Distance covered by wheel in 1 revolution = Perimeter of wheel.

So,

$\sf \: Distance \: covered \: by \: wheel \: in \: 1 \: revolution = 2 \pi \: r$

$\sf \: Distance \: covered \: by \: wheel \: in \: 450 \: revolution = 900 \pi \: r$

$\large \red{\bf \: According \: to \: statement} ✍$

☆Distance covered by wheel in 450 revolution = 900 m

$\begin{gathered}\bf\red{So,} \end{gathered}$

$\bf \:  ⟼ 900\pi \: r = 900$

$\bf \:  ⟼ \dfrac{22}{7} \times r = 1$

$\bf \:  ⟼ r = \dfrac{7}{22} \: m$

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$\large \green{\bf \: ⟼ Explore \: more } ✍$

Perimeter of rectangle = 2(length× breadth)

Diagonal of rectangle = √(length ²+breadth ²)

Area of square = side²

Perimeter of square = 4× side

Volume of cylinder = πr²h

T.S.A of cylinder = 2πrh + 2πr²

Volume of cone = ⅓ πr²h

C.S.A of cone = πrl

T.S.A of cone = πrl + πr²

Volume of cuboid = l × b × h

C.S.A of cuboid = 2(l + b)h

T.S.A of cuboid = 2(lb + bh + lh)

C.S.A of cube = 4a²

T.S.A of cube = 6a²

Volume of cube = a³

Volume of sphere = 4/3πr³

Surface area of sphere = 4πr²

Volume of hemisphere = ⅔ πr³

C.S.A of hemisphere = 2πr²

T.S.A of hemisphere = 3πr²