A car travels a certain distance taking 6 hours for onward journey. During the return journey the speed was increased by 20 km/hr and the return journey took a total time of 4 hours. What was the original speed?
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Answer:
Distance = x
Y= 6
D= xy
D= 6x------------(1)
Next:
Speed was increased by = (x+20)
D= xy
D=(x+20)4----------(2)
(1) &(2)
6x= (x+20)4
6x= 4x+80
2x=80
X=40
Answer is ::: 40
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