Question

A car travels a certain distance taking 7 hrs in forward journey, during the return journey increased speed 12km/hr takes the times 5 hrs.What is the distancetravelled

Answer 1

Let the speed of the forward journey = x kmph

Time taken for the forward journey = 7 hrs

The speed of the return journey = x+12 kmph

Time taken for the forward journey = 5 hrs

The distance travelled in both ways are equal.

7x = 5(x+12)

7x = 5x+60

7x-5x = 60

2x = 60

x = 60/2 = 30 kmph

The distance travelled = 7x = 7*30 = 210 kms