Question

A car travels a distance 100 m with a constant accelaration and average velocity of 20m/s. The final velocity acquired by the car is 25m/s .Find the initial velocity and the accelaration of the car

Answer 1

Answer:

initial velocity= 15 m/s

acceleration = 200  m$s^{-2}$

Explanation:

average velocity=20 m/s

Final velocity= 25 m/s

initial velocity = i =15 m/s

average velocity= final velocity+ initial velocity/2

20=25+i/2

20*2=25+i

40=25+i

i=40-25

i=15 m/s

Distance= 100 m

s=1/2 at²

100=1/2 a

a=200  m$s^{-2}$

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Answer 2

Answer: Initial velocity is 100m/s.

Explanation:

Distance= 100 m

Average velocity = 20m/s

Final velocity = 25 m/s

Let the initial velocity be u.

Let time in 1st interval be t1

t1= distance/speed

=100/u sec

Let time in 2nd interval be t2

t2=distance/ speed

=100/25 sec

Total time= t1+t2

=100/25+100/u

=100 (1/25+1/u)

=4 (u+25)/u

Average velocity: total distance/ total time

20=100/4 (u+25)/u

20=100 × u /4(u + 25)

20=25u / u+25

20u + 500 = 25u

500= 5 u

100= u

Therefore inituql velocity is 100m/s

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