Question

A car travels a distance 100 m with a constant acceleration and average velocity of 20 m/s. The final velocity acquired by the car is 25 m/s. Find : (i) the initial velocity (ii) acceleration of the car.

Answer 1

Answer:

Let distance and displacement of car be 200 m.

So,

Velocity= displacement/time.

So, time = displacement/velocity

Therefore,time =100/20=5second

Acceleration

according to s= v*t-1/2 a*t*t

200=20*5-1\2*a*5*5

a=8 m/s^2

so, initial velocity, (finalvelocity= 25m/s)

v=u+a*t

u= v-at

u= -15 m/s

Velocity can be negative.

Answer 2

Explanation:

EXPLANATION.

GIVEN

A car travel a distance 100 m with a constant

acceleration and average velocity of 20 m/s

The final velocity acquired by the car = 25 m/s

To find.

1) = The initial velocity.

2) = Acceleration of a car.

$average \: speed \: = \frac{distance}{time}$

=> 20 = 100 / T

=> T = 5 seconds.

average velocity= u+v/2

=> 20 = u + 25 / 2

=> 40 = u + 25

=> 15 = u

From Newton first equation of

kinematics.

=> v = u + at

=> 25 = 15 + 5t

=> 10 = 5a

=> a = 2 m/s²

Therefore,

1) = initial velocity = 15 m/s

2) = acceleration = 2 m/s²

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