Question

A car travels a distance 100m with a constant acceleration and average velocity of 20 m/s. The final velocity acquired by the car is 25 m/s. Find : the initial velocity and acceleration of the car PLEASE DON'T SEND ONLY ANSWER I WANT THE WHOLE NUMERICAL SOLUTION
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Answer 1

Answer:

Hi there !!

Here's your answer

Given,

Total distance (s) = 100m

Average velocity = 20m/s

Final velocity (v) = 25m/s

(1)We know,

Average velocity = u+v/2

=> 20 = u + 25/2

=> u = 15

Therefore,

The initial velocity is 15m/s

(2)Acceleration (a) = ?

Using the 3rd equation of uniform motion,

2as = v² - u²

2(a)(100) = (25)²-(15)²

200a = 400

a = 400/200

=> a = 2

Thus,

The acceleration is 2m/s²

Answer 2

$\large\bf\underline{Given:-}$

• Distance travelled by car = 100m with a constant acceleration and average velocity of 20 m/s.final velocity acquired by the car is 25 m/s.

$\large\bf\underline {To \: find:-}$

• initial velocity and acceleration of the car.

$\huge\bf\underline{Solution:-}$

• Distance (s) = 100m
• Average velocity = 20m/s
• Final velocity (v) = 25m/s
• Acceleration (a) = ?
• Initial velocity (u) = ?

We know that,

$\tt \star \:Average \: velocity = \frac{v + u}{2}$

➛ 20 = (u + 25)/2

➛ 20 × 2 = u + 25

➛ 40 = u + 25

➛ 40 - 25 = u

➛ 15 = u

So,

≫ Initial velocity of car is 15m/s.

Using third equation of motion :-

»★ v² = u² + 2as

➛ 25² = 15² + 2 × a × 100

➛625 = 225 + 200a

➛ 625 - 225 = 200a

➛ 400 = 200a

➛ a = 400/200

➛ a = 2m/s²

Hence,

• ≫ Acceleration of car = 2m/s²
• ≫ Initial velocity of car = 15m/s

$\rule{200}3$