Question

A car travels a distance 100m with a constant acceleration and average velocity of 20 m/s. The final velocity acquired by the car is 25 m/s. Find : the initial velocity and acceleration of the car PLEASE DON'T SEND ONLY ANSWER I WANT THE WHOLE NUMERICAL SOLUTION​

Answer 1

Final Velocity, V = 25 m/s

Avr velocity = 20 m/s

Avr velocity = ( initial + final ) / 2

20 = ( u + V ) / 2

40 = u + 25

u = 40 – 25

u = 15 m/s

Hence, intial velocity of the car = 15 m/s

using third equation of motion

v² – u² = 2as

25² – 15² = 2 a ( 100 )

625 – 225 = 200 a

400 = 200 a

a = 400 / 200

a = 2 m/s²

Hence, acceleration of the car was 2 m/s²

Answer 2

Answer:

Explanation:

Solution,

Here, we have

Distance covered, s = 100 m

Average velocity = 20 m/s

Final velocity, v = 25 m/s

To Find,

Initial velocity, u ?

Acceleration, a = ?

We know that,

Average velocity = u + v/2

⇒ 20 = u + 25/2

⇒ 10 = u + 25

⇒ u = 25 - 10

⇒ u = 15 m/s

Hence, the initial velocity is 15 m/s.

Now, acceleration,

According to the 3rd equation of motion,

We know that

v² - u² = 2as

⇒ (25)² - (15)² = 2as

⇒ 625 - 225 = 2 × a × 100

⇒ 400 = 200a

⇒ 400/200 = a

⇒ a = 2 m/s²

Hence, the acceleration is 2 m/s².