a car travels a distance 100m with a constant acceleration and average velocity is 20m/s the final velocity acquired by the car is 25m/s find (I) initial velocity and (ii) acceleration of car
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17
hey there,,,,,,
given:: s= 100m,,
V(av)= 20m/s
V(final)= 25m/s..
we know that average velocity
V(av)= V(final)+ V(initial)/2
20= 25+V/2
25+V= 40
V(initial)=15m/s
(ii) v^2- u^2= 2as
(25)^2- (15)^2= 2×100×a
625- 225= 200a
a= 400/200
a= 2m/s...
hope it is clear❕❕
given:: s= 100m,,
V(av)= 20m/s
V(final)= 25m/s..
we know that average velocity
V(av)= V(final)+ V(initial)/2
20= 25+V/2
25+V= 40
V(initial)=15m/s
(ii) v^2- u^2= 2as
(25)^2- (15)^2= 2×100×a
625- 225= 200a
a= 400/200
a= 2m/s...
hope it is clear❕❕
kundutapasi12:
thanks a lot
Answered by
12
this is your answer hope it help you
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