Question

A car travels a distance 50 km with a velocity 25 km h–1 and then 60 km with a velocity 20 km h–1 in the same direction. Calculate :
(i) the total time of journey
(ii) the average velocity of the car.

Answer 1

(i) 5 hours

(ii) 22.73 km/hr

Explanation:

Total distance travelled by the car = 50 + 60 = 110 km.

For the first phase, initial velocity u is zero and final velocity v is 25 km/hr

For the second phase, initial velocity u is 25 km/hr and final velocity is 20 km/hr

(i) Time = distance / velocity.

Time for first phase = 50 / 25 = 2 hours

Time for second phase = 60 / 20 = 3 hours.

Total time for travel = 2+3 = 5 hours.

(ii) Average velocity = D1V2 + D2V1 / (D1 + D2) = (50*20 + 60*25) / 50 + 60 = 1000 + 1500 / 110

= 2500 / 110  

= 22.73 km/hr

Answer 2

Explanation:

thank thank you please mark as brainliest I have copied from first one that's my fault