A car travels a distance 50 km with a velocity 25 km h⁻¹ and then 60 km with a velocity 20 km h⁻¹ in the same direction. Calculate :
(i) the total time of journey
(ii) the average velocity of the car.
Answers
Time = 5 hr ; average velocity = 22 km h⁻¹
Explanation:
A car travels a distance 50 km with a velocity 25 km h⁻¹ and then 60 km with a velocity 20 km h⁻¹ in the same direction.
Total distance traveled by the car during both phases of the journey = 50 + 60 = 110 Km.
(i) Total time taken to cover 110 Km = total of (distance / velocity) for both phases = 50/25 + 60/20 = 2 + 3 = 5 hours
(ii) Average velocity of the car = Total distance / total time (as the journey is in the same direction) = 110 / 5 = 22 km h⁻¹
Answer:
Explanation:
Time = 5 hr ; average velocity = 22 km h⁻¹
Explanation:
A car travels a distance 50 km with a velocity 25 km h⁻¹ and then 60 km with a velocity 20 km h⁻¹ in the same direction.
Total distance traveled by the car during both phases of the journey = 50 + 60 = 110 Km.
(i) Total time taken to cover 110 Km = total of (distance / velocity) for both phases = 50/25 + 60/20 = 2 + 3 = 5 hours
(ii) Average velocity of the car = Total distance / total time (as the journey is in the same direction) = 110 / 5 = 22 km h⁻¹