A car travels a distance of 100m with a constant acceleration and average velocity of 20m/s. The final velocity acquired by the car is 25m/s. Find:
1) Initial velocity
2) Acceleration of car
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Answers
Answered by
1
Answer:
Initial velocity = 15 m/s
Acceleration = 1.12 m/s^2
Explanation:
Let initial velocity be “x”
Average velocity = [initial velocity + final velocity] / 2
=> 20 = [25 + x] / 2
=> 40 = 25 + x
=> x = 15 m/s = initial velocity
We also know that v^2 - u^2 = 2*a*s
Where v = final velocity, u = initial velocity
a = acceleration, s = distance travelled
Substituting the values in the equation
(25)^2 - (20)^2 = 2*a*100
=>625 - 400 = 2*a*100
=>225 = 2*a*100
=> a = 225 / 200 = 1.12 m/s^2
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Answered by
1
Answer:
15 m/s and 2 m/s^2
Explanation:
u + 25 = 40
u= 40-25
=15 m/s
v^2 = u^2 = 2aS
625 = 225 + 200a
400/200 = a
2 m/s^2 = a
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