Question

A car travels a distance of 100m with a constant acceleration and average velocity of 20m/s .The final velocity acquired by the car is 25m/s. Find initial velocity and acceleration of the car


it's Isha​

Answer 1

Answer:

ans is 2/ ms ²

Step-by-step explanation:

average velocity =v+u /2

20=25+ u / 2

u = 15 m / s

v= u + at

25 = 15 + a x 5

we get a= 2m/s2

Answer 2

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Average velocity=(final velocity + initial velocity)/2

20 m/s = (25 m/s + initial velocity)/2

initial velocity = 40 m/s - 25 m/s

Therefore, initial velocity = 15 m/s

Now,

Let the initial velocity be u, final velocity be v, acceleration be a and distance travelled be S; then;

By Newton's third law of motion,

v² = u² + 2aS

or, v² - u² = 2aS

or, a = (v² - u²)/2S

or, a = {(25)² - (15)²}/(2×100) m/s²

or, a = {625 - 225}/200 m/s²

or, a = 400/200 m/s²

Therefore, a = 2 m/s²

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