Question

A car travels a distance
of 200m with a constant
acceleration and average velocity
of 10m/s. Thefinal velocity
acquired by the car is 15m/s. The
(a)initial velocity and
(b)acceleration of car is:
(i)(a) 5m/s
and (b) 0.5m/s
(ii) (a) 0.5m/s
and (b)=5m/s
(iii)(a) 5m/s
and (b)
0.5m/s^2
(iv)(a)0.5m/s
and (b)=5m/s^2​

Answer 1

Hello mate

Average velocity=

2

v+u

20=

2

25+u

u=15 m/s

v=u+at

25=15+a×5

We get, a=2 m/s

2

Answer 2

Explanation:

See this madarchod I am very helpful