Question

A car travels a distance of 300 km at a uniform speed. If the speed had
been 10 km/h less, then it would have taken 1 hour more to cover the same
distance. Represent the situation in the form of a quadratic equation​

Answer 1

X^2-10X+3000=0

Step-by-step explanation:

Let the speed be x

300/x -300/x-1300x

300x-3000-300x

____________ = 1

x^2-10x

x^2-10x+3000=0

Answer 2

The original speed of car is 60 km/hr.

Step-by-step explanation:

Since we have given that

Distance = 300 km

Let the original speed be 'x'

Let the new speed be 'x-10'

Time taken more = 1 hour

According to question, we get

$\dfrac{300}{x-10}-\dfrac{300}{x}=1\\\\\dfrac{300(x-(x-10)}{x^2-10x}=1\\\\\dfrac{x-x+10}{x^2-10x}=\dfrac{1}{300}\\\\\dfrac{10}{x^2-10x}=\dfrac{1}{300}\\\\3000=x^2-10x\\\\x^2-10x-3000=0\\\\x=-50,60$

So, the original speed of car is 60 km/hr.

# learn  more:

A car travels a distance of 300 km at a uniform speed. If the speed had

been 10 km/h less, then it would have taken 1 hour more to cover the same

distance. Represent the situation in the form of a quadratic equation

https://brainly.in/question/15892130