Question

A car travels a distance of 300 km at a uniform speed if the speed had been 10 kilometre per hour less than it would have taken 1 hour more to cover the same distance represent the situation in the form of a quadratic equation

Answer 1

Answer:

x² - 10x - 3000 = 0

Step-by-step explanation:

Let original speed and time taken be x & t resp.

ATQ :  =>  xt = 300                                → 1

          =>  (x-10)(t+1) = 300

          =>  t(x-10) = 310-x                       → 2

eqn 2 / eqn 1,

(x-10)/x = (310-x)/300

300x - 3000 = 310x - x²

x² - 10x -3000 = 0