Question

A car travels a distance of 560 km in 9.5 hrs partially at a speed of 40 kmph and remaining at 160 kmph. What is the distance it travels at the speed of 160 kmph ?

A. 120 km

B. 240 km

C. 320 km

D. 360 km

E. 420 km

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Answer 1

4:20 kilometer please like and reate five star

Answer 2

❋Question:

☛A car travels a distance of 560 km in 9.5 hrs partially at a speed of 40 kmph and remaining at 160 kmph. What is the distance it travels at the speed of 160 kmph ?

A. 120 km

B. 240 km✅✅

C. 320 km

D. 360 km

E. 420 km

❋Answer:

☛Given data are as follows:

• Total distance covered = 560 km
• Total time taken = 9.5 hours
• Partly with speed 40 and rest with 160.

↬ Let the distance covered with speed 40 = x

Then, the distance travelled with speed 160= 560-x

We know,

$⇢\large{ \sf{speed = \frac{distance}{time} }} \\ \\ ⇢ \large{ \boxed{ \green{ \sf{time = \frac{distance}{speed} }}}}$

↬ We have total time= 9.5 hours

☛That means,

Time taken to cover first part + time taken to cover second part = Total time taken.

$⇢ \large{ \sf{time \: taken \: in \: 1st \: part = \frac{x}{40} }} \\ \\ ⇢ \large{ \sf{time \: taken \: in \: 2nd \: part = \frac{560 - x}{160} }}$

☛The required equation would be

$⇢\large{ \sf{ \frac{x}{40} + \frac{560 - x}{160} = 9.5}} \\ \\ ⇢ \large{ \sf{ \frac{4x + 560 - x}{160} = \frac{19}{2} }} \\ \\ ⇢ \large{ \sf{ \frac{560 + 3x}{160} = \frac{19}{2} }} \\ \sf{ \underline{ \underline{ \star{ \green{ \: \: cross \: multiplying...}}}}} \\ \\ ⇢ \large{ \sf{2(560 + 3x) = 160 \times 19}} \\ \\ ⇢ \large{ \sf{1120 + 6x = 3040}} \\ \\ ⇢ \large{ \sf{6x = 1920}} \\ \\ ⇢ \large{ \sf{x = \cancel{ \frac{1920}{6}} = \boxed{320 \: km}}} \\ \\ \large{ \sf{ \boxed{ \therefore{560 - x = 560 - 320 = 240 \: km}}}}$

❋So final answer:

$\therefore{ \boxed{ \large{ \sf{ \orange{distance \: with \: speed 160 = 240 \: km}}}}}$

$\huge</u></strong><strong><u>{</u></strong><strong><u>\</u></strong><strong><u>therefore</u></strong><strong><u>{ \boxed{ \red{ \bold{ option \: b}}</u></strong><strong><u>}</u></strong><strong><u>}}$