A car travels a distance of 840 km at a uniform speed. If the speed of the car is 10km/h more then it takes 2 h less to cover the same distance. The original speed of the car was
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>let the original speed of the car be x
A.T.Q
840/x-840/x+10 =2
420x+4200-420x/x^2+10x =2
x^2+10x-4200 =0
x^2+70x-60x-4200 =0
( x+70)(x+60) =0
therefore X I.e original speed =60kmph
A.T.Q
840/x-840/x+10 =2
420x+4200-420x/x^2+10x =2
x^2+10x-4200 =0
x^2+70x-60x-4200 =0
( x+70)(x+60) =0
therefore X I.e original speed =60kmph
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