Question

A car travels a distance ‘x'on a straight road in two hours and then returns to the starting point in the next three hours. Its average speed is?​

Answer 1

Answer:

2x/5h

Explanation:

As per the provided information in the given question, we have :

• A car travels a distance "x" on a straight road in two hours and then returns to the starting point in the next three hours.

Suppose that the body's starting point is P. So, according to the question it travels x distance and comes to point Q in 2 hours . Then, it returns back to its initial position P, in next 3 hours.

We have to find the average speed. Average speed is the total distance covered divided by total time taken. So, we have to calculate total distance travelled and total time taken first.

↠⠀Total distance = PQ + QP

↠⠀Total distance = x + x

↠⠀Total distance = 2x

Similarly, now we'll calculate total time by adding the hours taken to cover from P to Q and Q to P.

↠⠀Total time = ( 2 + 3 ) h

↠⠀Total time = 5 h

As we know that,

↠⠀Average Speed = Total Distance ÷ Total time

↠⠀Average Speed = 2x ÷ 5h

↠⠀Average Speed = 2x/5h

Therefore, the average speed of the car is 2x/5h.

Answer 2

Answer: 2x/5 km/h.

Let the distance b/w initial point and final point be = (x) km.

∴ Total distance travelled = x + x = (2x) km

Now, total time taken = 2h + 3h = (5) h

We know,

Average speed = (Total distance)/(Total time)

=> v = (2x km)/(5 h)

=> v = 2x/5 km/h.