Question

a car travels a rate of 30km/hrs for 5min and then at 40km/hrs for 10 min find total distance travelled by the car and average speed of car.​

Answer 1

Speed of car for first 30 minutes = 30 km h^{-1}

Speed of car for next 1 hour = 40 km h^{-1}

(a) total distance travelled by the car

First case

Speed = distance / time

distance = speed x time

= 30 x 0.5 ---- (30 min = 0.5 hour)

= 15 km ---- (i)

Second case

speed = 40 km h^{-1}

distance = 40 km x 1

= 40 km ---- (ii)

Adding (i) and (ii)

Total distance = 15 km + 40 km

= 55 km

(b) total time of travel = 0.5 hr + 1.0 hr = 1.5 hr

(c) average speed = total distance travelled/total time taken

= 5.5 km/ 1.5 hr

= 36.67 km h^{-1}

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Answer 2

Physics

Chapters in CONCISE Physics - Middle School - 7

Exercises in Motion

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Question 6

Q6) A car travels with speed 30 km h-1 for 30 minute and then with speed 40 km h-1 for one hour. Find :

(a) the total distance travelled by the car

(b) the total time of travel

and

(c) the average speed of car

$\large\boxed{\rm\red{Solution \: \: by \: Ari14}}⇝$

Speed of car for first 30 minutes

$= 30 km h^{-1}$

Speed of car for next 1 hour

$= 40 km h^{-1}$

(a) total distance travelled by the car

First case

$Speed = distance / time$

$distance = speed \times time$

$= 30 \times 0.5 - - - (30 min = 0.5 hour)$

$= 15 km ---- (i)$

$Second \: case$

$speed = 40 km h^{-1}$

$distance = 40 km \times 1$

$= 40 km ---- (ii)$

$Adding (i) and (ii)$

$Total \: distance = 15 km + 40 km$

$= 55km$

(b) total time of travel = 0.5 hr + 1.0 hr = 1.5 hr

(c) average speed = total distance travelled/total time taken

$= 5.5 km/ 1.5 hr$

$= 36.67 km h^{-1}$