Question

A car travels a total distance of 150km. At the 50 minutes mark the car has travelled 50km and at the 110 minutes the car has travelled 120km. Find the average velocity in metres per second of the car between the 50-minute mark and the 110-minute mark. Round the final answer to 2 decimal places .​

Answer 1

Concept:-

Here, We first find the total distance covered between 50 minute mark and the 110 minute mark and also total time taken to travel the distance between 50 minute mark and 110 minute mark. Then we will find the average speed of the car.

Given:-

• Distance covered at the 50-minutes mark is 50 km.
• Distance covered at the 110-minutes mark is 120 km.

To Find:-

• Average velocity of the car between the 50-minutes mark and 110-minutes mark in meters/second ?

Solution:-

Here, The average velocity of an object is its displacement divided by the time it took. We'll have to assume that this car is going in a straight line as otherwise your question does not give us enough information to solve it.

So, the distance between 50-minutes mark and 110-minutes mark is of

$\huge \text{\Longrightarrow \triangle x \ =\ 120 - 50\ =\ 70\ km}$$\sf{\Longrightarrow \triangle x\ =\ 120 - 50\ =\ 70\ km}$

And, the time taken to cover the distance between 50-minutes mark and 110-minutes mark is of

$\sf{\Longrightarrow \triangle t\ =\ 110 - 50\ =\ 60\ s}$

Now, We need to convert these units to meters and seconds so that we get the correct units at the end.

$\sf{\Longrightarrow \triangle x\ =\ 70 \times 1000\ =\ 70,000\ m}$

$\sf{\Longrightarrow \triangle x\ =\ 60 \times 60\ =\ 3,600\ s}$

And so then we will find the average velocity by formula

$\sf{\Longrightarrow \dfrac{\triangle x}{\triangle t}}$

$\sf{\Longrightarrow \dfrac{70,000}{3,600}}$

$\sf{\Longrightarrow \dfrac{35}{18}\ m/s}$

$\sf{\Longrightarrow 1.94\ m/s}$

Hence, Average velocity of the car between the 50-minutes mark and 110-minutes mark in meters/second is 1.94 m/s.