A car travels a total distance of 300 km. After travelling a part of the distance without any trouble,
the car develops an engine problem and proceeds at
3/4th of its former speed and arrives at the destination
80 minutes late. Had the problem developed 50 km
further on, the car would have arrived 20 minutes
sooner. Find the original distance it travelled without
any problem, and the speed over that part of the
journey.
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Answer:
Train proceeds at 3/4 S where S is his usual speed means 1/4 decrease in the speed which will lead to 1/3 increase in the time.
[ As S *T = D, Speed is inversely proportional to time when distance is constant].
Now, the main difference come in those 24 km and the change in difference of time = 35 - 25 = 10 m
= 1 / 3 *T = 10 where T is the time required to cover the distance of (50 - 74) = 24 km
T = 30 min = 0.5 hours
Speed of the train = 24 / (0.5) = 48 kmph.
Step-by-step explanation:
hope it will help you
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