Question

A car travels a uniform speed of 30 km/h for 30 minutes and
then at uniform speed of 60 km/h for next 30 minutes. Calculate the average speed of the car.​

Answer 1

Answer:

Solution. For the first 30 km travelled, speed = 60 km/h. = 0.5 h-1 or 30 min. = 0.75 h-1 or 45 min.

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Answer 2

$\sf\underline\orange{Given:-}$

$\tt{\implies S_1 = 30km/h}$

$\tt{\implies T_1 = 30\:minutes}$

$\tt{\implies S_2 = 60km/h}$

$\tt{\implies T_2 = 30\:minutes}$

$\sf\underline\orange{To\:find:-}$

$\tt{\implies Average\:Speed}$

$\sf\underline\orange{Formulae\:applied:-}$

$\tt{\implies Total\:Distance = S_1 \times T_1 + S_2 \times T_2}$

$\tt{\implies Total\:Time = T_1 + T_2}$

$\tt{\implies Average\:Speed = \dfrac{Total\:Distance}{Total\:Time}}$

$\sf\underline\orange{Finding\:Total\:distance:-}$

$\tt{\implies Total\:Distance = S_1 \times T_1 + S_2 \times T_2}$

$\tt{\implies Total\:Distance = 30 \times 30 + 60 \times 30}$

$\tt{\implies Total\:Distance = 900 + 1800}$

$\tt{\implies Total\:Distance = 2700km}$

$\sf\underline\orange{Finding\:Total\:time:-}$

$\tt{\implies Total\:Time = T_1 + T_2}$

$\tt{\implies Total\:Time = 30+30}$

$\tt{\implies Total\:Time = 60\:minutes}$

$\sf\underline\orange{Converting\:Time\:from\:minutes\:to\:hour:-}$

$\tt{\implies Total\:Time = \dfrac{60}{60}hour}$

$\tt{\implies Total\:Time = 1\:hour}$

$\sf\underline\orange{Finding\:average\:speed:-}$

$\tt{\implies Average\:Speed = \dfrac{Total\:Distance}{Total\:Time}}$

$\tt{\implies Average\:Speed = \dfrac{2700}{1}}$

$\tt{\implies Average\:Speed = 2,700\:km/h}$

$\sf\underline\orange{Conclusion:-}$

$\tt{\implies Average\:Speed = 2,700\:km/h}$