A car travels along a straigt line for the first half time with speed 50kmph and the second half time with speed 60kmph.find the average speed of the car.
Answers
Answer:
The car travels straight path for first half time and second half time. The average speed for the travel journey is calculated over total distance travelled and total time for the travel.
Given, speed1 = 40 km/hr and speed 2 = 60 km/hr.
Let us assume that the total time taken for the travel be x.
So, we have, distance travelled in first half be, d 1=\text { speed } 1 \times {time 1}d1= speed 1×time1
Time taken for first half be time1 = half of total time
Time1=\frac{x}{2}Time1=
2
x
.
\begin{lgathered}\begin{aligned} \mathrm{d} 1 &=40 \times\left(\frac{x}{2}\right) \\ d 1 &=20 x \end{aligned}\end{lgathered}
d1
d1
=40×(
2
x
)
=20x
And, distance travelled in second half be, \mathrm{d} 2=\text { speed } 2 \times \text { time } 2d2= speed 2× time 2
Time taken for second half be time2 = half of total time
Time2=\frac{x}{2} m.Time2=
2
x
m.
\begin{lgathered}\begin{array}{l}{\mathrm{d} 2=60 \times\left(\frac{x}{2}\right)} \\ {\mathrm{d} 2=30 x}\end{array}\end{lgathered}
d2=60×(
2
x
)
d2=30x
Thereby, Average speed = total distance / total time
Total distance \begin{lgathered}\begin{array}{l}{=d 1+d 2} \\ {=20 x+30 x} \\ {=50 x}\end{array}\end{lgathered}
=d1+d2
=20x+30x
=50x
Total time = x
Average speed \begin{lgathered}\begin{array}{l}{=\frac{50 x}{x}} \\ {=50 \mathrm{km} / \mathrm{hr}}\end{array}\end{lgathered}
=
x
50x
=50km/hr
HEY MATE! here is your answer
Explanation:
for the first half the car travels along the straight line with the speed 50 km per hour i.e.
=1/2 ×50=25kmph.
first second half the car travels with the speed of 60 kilometre per hour i.e.
=1/2×60=30kmph.
NOW,add up both speeds =25+30=55 kmph is the right answer.
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