Question

A car travels along the line OX with a uniform
acceleration. At times t1 and t2 its positions are x1
and x2 respectively. Then its acceleration is (assume
that at t = 0 the car is at O)
(1) 2(x1t2 -x2t1) / t1t2(t2-t1)
(2)2(x2t1 -x1t2) / t1t2(t2-t1)
(3) 2(x1t2 -x2t1) / t1t2 (t2+t1)
(4)2(x2t1 -x1t2) / t1t2(t2+t1)​

Answer 1

Answer:

very pleasant good morning bro..

Answer 2

Please post the question properly