Question

A car travels along the route PQRST in 30 minutes. What is the average speed. show your working.

Answer 1

Explanation:

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Answer 2

Answer- The above question is from the chapter 'Kinematics'.

Some important terms and formulae:-

1. Velocity- It is the displacement per unit time.

S.I. Unit of Velocity- m/s

It is a vector quantity as it possesses magnitude and direction.

2. Acceleration- It is the rate of change of velocity.

S.I. Unit of Acceleration- m/s²

It is also a vector quantity.

Negative acceleration is called retardation.

3. Distance- It is the path length transversed by an object.

S.I. Unit of Distance- m

It is a scalar quantity.

4. Displacement- It is the shortest distance between the initial and final point.

S.I. Unit of Displacement- m

It is a vector quantity.

5. Equations for uniformly accelerated motion-

Let u = Initial velocity of a particle

v = Final velocity of a particle

t = Time taken

s = Distance travelled in the given time

a = Acceleration

1) v = u + at

2) s = $\frac{1}{2}$ at² + ut

3) v² - u² = 2as

6. Average Speed = Total distance ÷ Total time

7. Average Velocity = Total displacement ÷ Total time

Given question: A car travels along the route PQRST in 30 minutes. What is the average speed? Show your working.

Answer: Total distance = PQ + QR + RS + ST

                                        = 10 + 5 + 10 + 5

                                        = 30 km

Total time = 30 minutes = $\frac{1}{2}$ h

Average Speed = Total distance ÷ Total time

                           = 30 ÷ 1/2

                           = 30 × 2

                           = 60 km/h

∴ Average Speed  = 60 km/h.