Math, asked by amalsuleman8011, 6 months ago

a car travels at 20m/s for 15 seconds before it comes to rest by decelerating at 2.5 m/s^2 .find the total distance travelled​

Answers

Answered by unnathibadam52
2

Step-by-step explanation:

11th

Physics

Motion in a Straight Line

Problems on Equation of Motion

Acar travels with a uniform...

PHYSICS

Acar travels with a uniform velocity of 20ms

−1

for 5 sec. The brakes are then applied and the car is uniformly retarded. It comes to rest in further 8 sec. by drawing a graph between velocity and time-find.

The distance traveled in the first 5 sec.

The distance traveled after the brakes are applied.

Total distance traveled.

Acceleration during the first 5 sec.

Acceleration during the last 8 sec.

HARD

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CALCULATOR

Enter the know values to find unknown

Acceleration

Distance

Final Velocity

v = u + a*t

Initial Velocity u

m/s

Final Velocity v

m/s

Time t

s

Acceleration a

m/s²

RESET VALUES

ANSWER

Given, u=20m/s

t

1

=5s

t

2

=8s

Graph: (Refer to Image)

(1) Distance travelled in first 5 sec= area of ABDE= 20×s=80m

(2) Distance travelled after the brakes are applied (area of BCD)=

2

1

×8×5=20m

(3) Total distance travelled= AreaofABCDE+AreaofBCD=80+20=100m

(4) Acceleration during the first 5 sec= 0, because uniform velocity.

(5) Acceleration during the last 8 sec= v=0,u=20m/s,t=8sec

⇒v=u+at⇒0=20+a(8)

⇒a=−2.5m/s

2

(slope of the line DC)..

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