a car travels at 20m/s for 15 seconds before it comes to rest by decelerating at 2.5 m/s^2 .find the total distance travelled
Answers
Step-by-step explanation:
11th
Physics
Motion in a Straight Line
Problems on Equation of Motion
Acar travels with a uniform...
PHYSICS
Acar travels with a uniform velocity of 20ms
−1
for 5 sec. The brakes are then applied and the car is uniformly retarded. It comes to rest in further 8 sec. by drawing a graph between velocity and time-find.
The distance traveled in the first 5 sec.
The distance traveled after the brakes are applied.
Total distance traveled.
Acceleration during the first 5 sec.
Acceleration during the last 8 sec.
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CALCULATOR
Enter the know values to find unknown
Acceleration
Distance
Final Velocity
v = u + a*t
Initial Velocity u
m/s
Final Velocity v
m/s
Time t
s
Acceleration a
m/s²
RESET VALUES
ANSWER
Given, u=20m/s
t
1
=5s
t
2
=8s
Graph: (Refer to Image)
(1) Distance travelled in first 5 sec= area of ABDE= 20×s=80m
(2) Distance travelled after the brakes are applied (area of BCD)=
2
1
×8×5=20m
(3) Total distance travelled= AreaofABCDE+AreaofBCD=80+20=100m
(4) Acceleration during the first 5 sec= 0, because uniform velocity.
(5) Acceleration during the last 8 sec= v=0,u=20m/s,t=8sec
⇒v=u+at⇒0=20+a(8)
⇒a=−2.5m/s
2
(slope of the line DC)..
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