Question

A car travels at a constant
speed of 5 m/sec for 2 sec
then accelerates at a rate
of 4 m/sec^2 for 3 sec.
What is the total distance
traveled by the car ?​

Answer 1

Answer:

Explanation:

Answer: Explanatlon: ⇒ It Is given that, Speed of a car =30m/s Radius of circular track =500m. Its speed is increasing at the rate of 2m/s2. Acceleration =? ⇒ Total acceleration Is equal to the root of the squared sum of centripetal acceleratlon and tangentlal acceleration. Thus, centripetal acceleration, a−n=v2/ radius =302/500 Tangential acceleration, a−t=2m/s2 ⇒ Total acceleration: a− total =a–√−t2+a−n2 =2–√2+(302/500)2 =2–√2+1.82 =4–√+3.24 =7–√.24 =2.7m/s2 Thus, the value of the acceleration of a car Is 2.7m/s2.