Question

A car travels at a uniform speed of 30km/hr for 30 minutes and then at a uniform speed of 60 Km/hr for the next 40 minutes. Calculate the total distance travelled by the car and its average velocity.​

Answer 1

Answer:

Answer Expert Verified

Hence Average Velocity is 48km/hr and total time of journey = 5/4 hours. or Total Time Taken = 60/48

Answer 2

Answer:

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Explanation:

$so \: here \: \\ speed \: (s1) = 30. \frac{km}{hr} \\ \\ time \: taken(t1) = 30.mins = \frac{1}{2.} hr = 0.5 \: hours \\ \\ so \: we \: know \: that \\ speed = \frac{distance}{time} \\ ie \: then \\ 30 = \frac{d1}{0.5} \\ d1 = 30 \times 0.5 \\ = 15.0 \\ = 15.km \\ hence \: d1 \div 15.km$

$simiarly \\ speed \: (s2) = 60.Km/hr \\ time \: taken \: (t2) = 40.minutes = \frac{2}{3} \: hours \\ \\ so \: now \: using \\ speed = \frac{distance}{time} \\ \\ s2 = \frac{d2}{t2} \\ \\ 60 = \frac{ \frac{d2}{2} }{3} \\ \\ = 60 = \frac{3.d2}{2} \\ ie \: 60 \times 2 = 3.d2 \\ 120 = 3d2 \\ ie \: d2 = 40.km$

$so \: thus \: then \\ we \: know \: that \\ velocity = \frac{distance}{time} \\ \\ thus \: then \: total \: velocity = \frac{combined \: distance}{total \: time} \\ \\ = \frac{40 + 30 }{ \frac{1}{2} + \frac{2}{3} } \\ \\ = \frac{ \frac{70}{(3 \times 1) + (2 \times 2)} }{ 3\times 2} \\ \\ = \frac{ \frac{70}{ 3+ 4} }{6} \\ \\ = \frac{6 \times 70}{7} \\ \\ = 6 \times 10 \\ \\ = 60. \frac{m}{s}$