a car travels at a uniform velocity of 30 metre per second for 5 seconds the brakes are then applied and a car comes to rest with uniform retardation in a further eight seconds draw a sketch the graph of velocity against against time to how far does the car travel after the brakes are applied
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let S be distance traveled by the car after application of brake
given
initialvelocity of car after applying brakes (u) 30 m/s
retardation of the car (a)=(v-u)/t
a=(0-30)/8
a=-30/8
a=-15/4 m/s^2
according to the equation of motion
{( v^2 - u^2 )=2aS} final velocity v=0
0-30^2=2×(-15/4)×S
S= (-900×2)/(-15)
S =120m
the distance travelled by the car travel after the brakes are applied is 120 meters
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